Fiber Optics


It’s Time You Learn About Fiber Optics & Formulas

For the better part of the American population fiber optics is a mystery to them. However, the fiber optics & formulas it pertains are actually part of a not-so-complicated branch of Applied Science. School yourself about fiber optics, added knowledge isn’t a wasted experience, and anyone can always afford to have additional awareness. Don’t be distraught by all the terms encountered, on the other hand. Applied Science isn’t as frightening as it seems. It is in fact quite easy, as long as you follow this discussion of fiber optics & formulas in every detail.

So here goes:

What is Fiber Optics? It is a branch of Applied Science and Engineering, the former being a practical science of applying facts from other natural scientific incident to another practical problems. In our case, the incident is how light can travel through the entire length of a glass tube, provided that it meets a certain criteria: there shouldn’t be so much impurities in the glass as to decrease, absorb, or reflect the relay of light.

This light relaying property is called Refractive Index, or Index of Refraction. It is the ability of the substance to reflect the light within the confines of its body, thus traveling through its entire length. So, illustratively, if you introduce a light source on one end of the fiber optic thread, the light travels along its entire body (illuminating the material by doing so) and dispersing the light at the opposite end –strongly.

Take for instance this picture: http://en.wikipedia.org/wiki/Image:Fiber_optic_bundle.jpg

You see, the hidden end should have the light source, thus allowing the light to travel along its entire length. Notice how the light somewhat “dimmed” at the point where it was slightly bending? You should also notice that the hand was clearly illuminated. This is the dispersion of the light onto the hand, a phenomenon of light escaping onto the sides by the bending of the optical fibers. Now imagine if these fibers are coated with a material with lower Index of Refraction? There will be no light spilt, and the light carried onto the opposite end will be fuller and stronger. Why? Because being coated with a low refractive index material and with the fiber having a high refractive index the light is “contained”, even if the wires are bent.

So therefore, we know that the Index of Refraction plays an integral part in the transmission of light along the entire fiber. Thus for the fiber optics & formula:

RI of the medium = [186 x 10-3 ÷Speed of light in medium]

Where:
RI is the Refractive Index
186 x 10-3 is the speed of light in optimal (vacuum) conditions

 

 

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Fiber Optics


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